Select or generate n random numbers / items from list in Asp.net C#

Introduction: In this article I am going to explain how to get n random numbers from list of numbers in asp.net c# using LINQ. 

In previous articles i explained Difference between IEnumerable and IQueryable in c# with example and Get checkboxlist selected items in comma separated format in asp.net(c#,vb) and Convert generic list to datatable in asp.net c#,vb and Jquery UI autocomplete textbox with database inasp.net c#,vb with example and Validate,upload,crop and store image in folder in asp.net using jquery

Description: While working on project i got the requirement to get n random numbers from list. I was able to get this requirement fulfilled very easily using LINQ. I am going to share this with all so that it might help me and others in future. 

Implementation: Let’s understand by an example. 

    protected void btnSubmit_Click(object sender, EventArgs e)

    {

        List<int> list = new List<int>() { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 };

        List<int> randomNumberList = new List<int>();

        randomNumberList = GetRandomElements(list, 3);

    }

  public List<t> GetRandomElements<t>(IEnumerable<t> list, int elementsCount)

    {

        return list.OrderBy(x => Guid.NewGuid()).Take(elementsCount).ToList();

    }

On first run it produced result as:

On second runt the result was:

Now over to you:

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